SOLVED Hiding elements depending on fom status

[Trembowiecki]

Hi!

I bet people before me had such problems, but I just can't find it on the forum, so I'm really sory, if I duplicate something here.

I try to show/hide element on my form, depending on form's status - I mean if it's a new record or edit record form. I know this can be achieved with the help of form php plugin, but I have no idea how to er... call these two forms in 'php code' window.

Cheers,

Olek

 

[juuser]

You need element Javascript for that. Go to the "id" element's settings -> Javascript -> Add new.

Event: Load
If this elemenent: ==
Value: leave empty (that means new record)
Action: hide
Element/Group: choose which one to hide

And for the existing record just select "!=" in "If this element" field.

 

[Trembowiecki]

Thank you for your prompt answer. My bad - I wanted my question to be as concise as possible. I want to use form php plugin for this scenario:

1) new record = element (radio) hidden + plugin forces onBeforeProcess storing predefined value (one of radio element's options),
2) edit = element (radio) is shown with value (different than the one already stored in db) forced onLoad.

I know how to code most of it, except the part when I have to call new or edit form for my condition.

Once again, I'm sorry for the confusion.

 

[juuser]

OK, then it's another story.

In form php plugin get the rowid like that:

$myrowid= $formModel->getElementData('mytable___id');

And then do the comparing something like:

if($myrowid != "") {
is existing record, do something
etc...

 

[Trembowiecki]

That makes a perfect sense. Thank you!