[SOLVED] Redirect Form call a PHP with POST method

[linque]

Hi,
How can I create a Form with a redirect the call to a PHP with a Post Method.
I use the plug-in 'redirect' but I receive data only with Get Method.
Thank's in advance for the answers...

 

[troester]

You can use the php form plugin to do nearly anything you want to do.

Gesendet von meinem SM-G930F mit Tapatalk

 

[linque]

I don't see how to send data like the following code for example :

<form action="/url" method="POST">
<div>
<label for="say">Quelle salutation voulez-vous dire ?</label>
<input name="say" id="say" value="Salut">
</div>
<div>
<label for="to">A qui voulez-vous le dire ?</label>
<input name="to" id="to" value="Maman">
</div>
<div>
<button>Envoyer mes salutations</button>
</div>
</form>

 

[troester]

This is HTML, not php

 

[linque]

This is HTML, not php

think a little bit please !
" <form action="/url" method="POST"> "
the URL is a PHP calling with a POST Method !

 

[lousyfool]

@linque:

Fabrik forms are using method="post".
A form redirect plugin as mentioned in your initial post lets you only specify a different URL than the default list on form submission -- that's all. So, pretty sure that's not what you want.
If you want the form data to process it with your own custom PHP, you should indeed use a PHP form plugin -- as @troester already said.

The Wiki here might not be perfect, but the links given should be good reads for you and this specific use case.

 

[deant]

Redirect and/or open new tab in php form plugin can be quite trickey. Can you be more specific what you want to do?

And again " <form action="/url" method="POST"> " is HTML

 

[linque]

Thank's for your answers.
I found the solution.

Create a FORM adding a button
Add au Javascript 'OnClick'
Use for example the following script :

const form = document.createElement('form');
form.method = 'post';
form.action = '/test.php';
form.target = '_blank';
document.body.appendChild(form);

const formField = document.createElement('input');
formField.type = 'hidden';
formField.name = 'FieldID';
formField.value = $('___FieldToSend').value;
form.appendChild(formField);
form.submit();